Bella Ciao solution in C language.- Codechef

  

Bella Ciao

Problem Code: CHFHEIST

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Chef is planning a heist in the reserve bank of Chefland. They are planning to hijack the bank for $�$ days and print the money. The initial rate of printing the currency is $�$ dollars per day and they increase the production by $�$ dollars after every interval of $�$ days. For example, after $�$ days the rate is $�+�$ dollars per day, and after $2�$ days the rate is $�+2�$ dollars per day, and so on. Output the amount of money they will be able to print in the given period.

Input Format

The first line contains an integer $�$, the number of test cases. Then the test cases follow.

Each test case contains a single line of input, four integers $�,�,�,�$.

Output Format

Output For each test case, output in a single line the answer to the problem.

Constraints

• $1\le �\le 10^5$
• $1\le �\le �\le 10^6$
• $1\le �,�\le 10^6$

Subtask #1 (15 points): $�\le �\le 100$

Subtask #2 (85 points): original constraints

Sample Input 1 

3
2 1 1 1
3 2 1 1
5 2 1 2

Sample Output 1 

3
4
13

Explanation

Test Case $1$:
On the first day, the rate of production is $1$ dollar per day so $1$ dollar is printed on the first day.
On the second day, the rate of production is $1+1=2$ dollars per day so $2$ dollars are printed on the second day.
The total amount of money printed in $2$ days is $1+2=3$ dollars.
Test Case $2$:
For the first two days, the rate of production is $1$ dollar per day so $1\cdot 2=2$ dollars are printed on the first two days.
On the third day, the rate of production is $1+1=2$ dollars per day so $2$ dollars are printed on the third day.
The total amount of money printed in $3$ days is $2+2=4$ dollars.
Test Case $3$:
For the first two days, the rate of production is $1$ dollar per day so $1\cdot 2=2$ dollars are printed on the first two days.
On the next two days, the rate of production is $1+2=3$ dollars per day so $3\cdot 2=6$ dollars are printed on the next two days.
On the last day, the rate of production is $3+2=5$ dollars per day so $5$ dollars are printed on the last day.
The total amount of money printed in $5$ days is $2+6+5=13$ dollars.

. . .
Solution in C.

#include <stdio.h>

int main(void) {
	int t;
	scanf("%d",&t);
	while(t--){
	    int a, b;
	    scanf("%d %d",&a,&b);
	    int sum = a+b;
	    if(a>b){
	        printf("%d %d\n",a,sum);
	    }
	    else{
	        printf("%d %d\n",b,sum);
	    }
	}
	return 0;
}